Question

The length of rectangle R is $10$ per cent more than the side of Square S. The width of the rectangle is $10$ per cent less than the side of the square. The ratio of the areas, R : S, is:

• A. $99:100$
• B. $101:100$
• C. $1:1$
• D. $199:200$
• E. $201:200$

Answer 1

Answer: (A)

$99:100$

Let s be the side of the square.

$l=\frac{11s}{10},b=\frac{9s}{10}\frac{Area\left(R\right)}{Area\left(S\right)}=\frac{lb}{s^2}=\frac{\frac{99s^2}{100}}{s^2}=99:100$