Question

The length of the common chord of the ellipse $\frac{{(x-1)}^2}{9}+\frac{{(y-2)}^2}{4}=1$ and the circle ${(x-1)}^2+{(y-2)}^2=1$ is:

• A. $1$
• B. $3$
• C. $8$
• D. None of these

Answer 1

Answer: (D)

None of these

Given circle $(x-1{)}^2+(y-2{)}^2=1$
Center is at $(1,2)$ and radius $=1$
Given ellipse $\frac{{(x-1)}^2}{9}+\frac{{(y-2)}^2}{4}=1$
Center is at $(1,2)$
Clearly, the circle and ellipse do not meet at any point.
Hence, option D is correct.