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Question

The length of the common chord of
x2+y2+2x+3y+1=0, x2+y2+4x+3y+2=0 is

A
2
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B
2
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C
22
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D
4
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Solution

The correct option is C 22
x2+y2+4x+3y+2=0
radius =4+942
=2+94
==172
x2+y2+2x+3y+1=0
radius =1+941
=3/2
Oo=1
Mn=1/2
OP2=Pm2+Om2
94=Pm2+14 Pm284 2 Pm=2
PQ=22


1373633_1168601_ans_a84eea2208ec41bda09bafcdd63b9f17.png

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