The length of the diagonal of a quadrilateral is $40 c m$ and the perpendicular drawn to it from the opposite vertices are $12 c m a n d 7.5 c m$ . Find the area of the quadrilateral.

380 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

382 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

390 c m^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

392 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $390 c m^{2}$
Given:
$d = 40 c m$
$h_{1} = 12 c m$
$h_{2} = 7.5 c m$

Area of quadrilateral $= \frac{1}{2} d (h_{1} + h_{2})$

$= \frac{1}{2} \times 40 (12 + 7.5) = 20 \times 19.5 = 390 c m^{2}$

Suggest Corrections

Similar questions

Q. A diagonal of a quadrilateral is

26 c m

and the perpendiculars drawn to it from the opposite vertices are

12.8 c m

and

11.2 c m

. Find the area of the quadrilateral.

Find the area of a quadrilateral one of whose diagonals is $40 c m$ and the lengths of the perpendiculars drawn from the opposite vertices on the diagonal are $16 c m$ and $12 c m$ .

Q. Mark (✓) against the correct answer:
The diagonal of a quadrilateral is 20 cm in length and the lengths of perpendiculars on it from the opposite vertices are 8.5 cm and 11.5 cm. The area of the quadrilateral is
(a) 400 cm²
(b) 200 cm²
(c) 300 cm²
(d) 240 cm²

Q. Find the area of quadrilateral whose diagonal is of length

70 m

and lengths of the perpendiculars drawn from the opposite vertices on the diagonal are of lengths

42 m

and

50 m

respectively.

One diagonal of a quadrilateral is 35 centimetres long and the perpendiculars to it from the opposite vertices are 15 centimetres and 19 centimetres long. What is the area of this quadrilateral?

Join BYJU'S Learning Program

The length of the diagonal of a quadrilateral is 40cm and the perpendicular drawn to it from the opposite vertices are 12cmand7.5cm. Find the area of the quadrilateral.

The correct option is C 390cm2Given:d=40cmh1=12cmh2=7.5cmArea of quadrilateral =12d(h1+h2)=12×40(12+7.5)=20×19.5=390cm2

The length of the diagonal of a quadrilateral is $40 c m$ and the perpendicular drawn to it from the opposite vertices are $12 c m a n d 7.5 c m$ . Find the area of the quadrilateral.

The correct option is C $390 c m^{2}$
Given:
$d = 40 c m$
$h_{1} = 12 c m$
$h_{2} = 7.5 c m$

Area of quadrilateral $= \frac{1}{2} d (h_{1} + h_{2})$

$= \frac{1}{2} \times 40 (12 + 7.5) = 20 \times 19.5 = 390 c m^{2}$