The length of the diagonal of a rhombus is 24 cm. If the side of the Rhombus is 13 cm, find the length of the other diagonal.
Let the rhombus be ABCD, Let the intersecting point of the diagonals be O
Given,
AB=BC=CD=AC=13cm
AC=24cm
Since the diagonals of a rhombus bisect each other at right angles a right triangle BOC is formed.
According to the Pythagoras Theorem,
(BO)²+(CO)²=(BC)²
Since the diagonals bisect each other CO=CA/2
=24cm/2=12cm
Therefore,
(BO)²+(CO)²=(BC)²
(BO)²=(BC)² - (CO)²
(BO)²=(13cm)² - (12cm)²
(BO)²=(169-144)cm
BO=sqrt(25)cm
=5cm
Therefore its other diagonal is (5cm*2)
ie.10cm long