Question

The length of the diagonal of a square is $\left(a+b\right)$ then its perimeter is

• A. $4\left(a+b\right)$
• B. $2\sqrt{2}\left(a+b\right)$
• C. $\sqrt{2}\left(a+b\right)$
• D. None of these

Answer 1

Answer: (B)

$2\sqrt{2}\left(a+b\right)$

Let the side of the square be $x$.

Since, the diagonal $=(a+b)$

We know that

$\sqrt{2}x=(a+b)$

$x=\frac{(a+b)}{\sqrt{2}}$

We know that the perimeter of the square

$=4x$

Therefore,

$=\frac{4(a+b)}{\sqrt{2}}$

$=2\sqrt{2}(a+b)$

Hence, this is the answer.