Question

The length of the diagonals of a rhombus are $16$ cm and $12$ cm. The side of the rhombus is

• A. $10$ cm
• B. $12$ cm
• C. $9$ cm
• D. $8$ cm

Answer 1

The correct option is A $10$ cm

Diagonals of rhombus are cut each other at ${90}^o$.
Since $d_1=16$and $d_2=12$
Therefore, by Pythagoras theorem
$a^2={\left(\frac{d_1}{2}\right)}^2+{\left(\frac{d_2}{2}\right)}^2$
$\Rightarrow$ $a^2=8^2+6^2$
$\Rightarrow$ $a=\sqrt{100}=10$