The length of the diameter of the circle $x^{2} + y^{2} - 4 x - 6 y + 4 = 0$ is -

9

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3

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4

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6

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Solution

The correct option is D $6$
Given that:

$x^{2} + y^{2} - 4 x - 6 y + 4 = 0........ (1)$

Since we now that the standred equation of circle is $x^{2} + y^{2} + 2 g x + 2 f y + c = 0........ (2)$ and radius is = $\sqrt{g^{2} + f^{2} - c}$

Then comapiring equation 1 and 2.

$g = - 2, f = - 3, c = 4$ ,then radius= $\sqrt{(- 2)^{2} + (- 3)^{2} - 4}$

Radius= $3$ .
$D i a m e t e r i s = 2 \times r a d i u s$ .

$D i a m e t e r = 2 \times 3 = 6$ .

Suggest Corrections

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(2, 1)

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