Question

The length of the hypotenuse of a right-angled triangle whose two legs measure $4cm$ and $0.03m$ is-

Answer 1

0.03 m = 0.03$\times$ 100 cm
= 3 cm
We have
${\left(hypotenuse\right)}^2={\left(side\right)}^2+{\left(side\right)}^2$
$={\left(4\right)}^2+{\left(3\right)}^2$
= 16+9
= 25
Hypotenuse=$\sqrt{25}$= 5 cm