Question

The length of the intercept on y-axis cut off by the parabola, $y^2-5y=3x-6$ is:

• A. $1$
• B. $2$
• C. $3$
• D. $5$

Answer 1

The correct option is A $1$

$ony-axis,anypointwillhavexvalueaszero$

$\therefore y^2-5y=(3\times 0)-6$

$or{y}^2-5y+6=0$

$(y-3)(y-2)=0$

$\therefore y=2,x=0|y=3,x=0$

$\therefore lengthofintercept=\sqrt{(0-0{)}^2+(3-2{)}^2}$

$=1unit$