The length of the latus rectum of the hyperbola $9 x^{2} - 16 y^{2} - 72 x - 32 y - 16 = 0$ is

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Solution

The correct option is A
Given hyperbola is $\frac{(x + 4)^{2}}{16} - \frac{(y + 1)^{2}}{9} = 1$
$∴$ Length of the latus rectum is $\frac{2 b^{2}}{a} = \frac{9}{2}$

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