Question

The length of the latusretum of the ellipse 3x² + y² = 12 is ___________.

Answer 1

Given ellipse is 3x² + y² = 12
$\mathrm{i}.\mathrm{e}\frac{x^2}{4}+\frac{y^2}{12}=1$
​i.e a² = 4 and b² = 12
$\therefore$ Length of latus rectum is $\frac{2b^2}{a}$ =$\frac{2\times 12}{2}=12$