Question

The length of the longest rot that can be kept inside a box of dimensions 12 cm$\times 3\sqrt{3}$ cm $\times$5 cm is

Answer 1

$=\sqrt{l^2+b^2+h^2}$

$=\sqrt{(12{)}^2+(3\sqrt{3}{)}^2+(5{)}^2}$

$=\sqrt{144+27+25}$

$=\sqrt{196}$

$=14$

The length of the longest rot that can be kept inside a box of dimensions $12$cm $\times 3\sqrt{3}$cm $\times 5$cm is $14$.