The length of the major axis of the ellipse 5x - 102 - 5y - 152 - 3x - 4y - 72-9 is

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Question

The length of the major axis of the ellipse $(5 x - 10)^{2} + (5 y + 15)^{2} = \frac{(3 x - 4 y + 7)^{2}}{9}$ is

10

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\frac{15}{4}

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\frac{20}{3}

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4

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(5 x - 10)^{2} + (5 y + 15)^{2} = \frac{(3 x - 4 y + 7)^{2}}{4},

k

3 k =

(5 x - 10)^{2} + (5 y + 15)^{2} = \frac{(3 x - 4 y + 7)^{2}}{4},

k

3 k =

(5 x - 10)^{2} + (5 y + 15)^{2} = \frac{(3 x - 4 y + 7)^{2}}{4}

(5, 0) (- 5, 0)

3 x - 5 y - 9 = 0

12 x^{2} + 4 y^{2} + 24 x - 16 y + 25 = 0

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