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Question

The length of the minute hand of a clock is 5 cm. Find the area swept by the minute hand during the time period 6:05 am and 6:40 am.

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Solution



We know that, in 60 min, minute hand revolving =360

In 1 min, minute hand revolving =36060

In ( 6:05 am to 6:40 am) = 35 min

Minute hand revolving =36060×35=6×35

Given that, length of minute hand (r) = 5cm

Area of sector AOBA with angle O=π×r2360×O

=227×(5)2360×6×35

=227×5×5360×6×35

=22×5×5×560

=2756=4556cm2

Hence, the required area swept by the minute land is 4556cm2.

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