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Byju's Answer

Standard XII

Physics

Deviation in Prism

The length of...

Question

The length of the optical path of two media in contact of lengths $d_{1}$ and $d_{2}$ of refractive indices $μ_{1}$ and $μ_{2}$ respectively is

μ_{1} d_{1} + μ_{2} d_{2}

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\frac{μ_{1} d_{2} + μ_{2} d_{1}}{μ_{1} μ_{2}}

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\frac{d_{1} d_{2}}{μ_{1} μ_{2}}

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\frac{d_{1} + d_{2}}{μ_{1} μ_{2}}

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Solution

The correct option is A $μ_{1} d_{1} + μ_{2} d_{2}$
Option A is correct

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A vessel of depth $2 d c m$ is half filled with a liquid of refractive index $μ_{1}$ and the upper half with a liquid of refractive index $μ_{2}$ . The apparent depth of the vessel seen perpendicularly is

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Q. A right angled prism of refractive index

μ_{1}

is placed in a rectangular block of refractive index

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, which is surrounded by a medium of refractive index

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as shown in the figure. A ray of light

^{'} e^{'}

enters the rectangular block at normal incidence. Depending upon the relationship between

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it takes one of the four possible paths

^{'} e f^{'},^{'} e g^{'},^{'} e h^{'}

^{'} e i^{'}

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List -I

with conditions of refractive indices in

List -II

and choose the correct answer.
List - I List - II

$(P) e \to f$	$(1) μ_{1} > \sqrt{2} μ_{2}$
$(Q) e \to g$	$(2) μ_{2} > μ_{1} & μ_{2} > μ_{3}$
$(R) e \to h$	$(3) μ_{1} = μ_{2} = μ_{3}$
$(S) e \to i$	$(4) μ_{2} < μ_{1} < \sqrt{2} μ_{2} & μ_{2} > μ_{1}$