The length of the parallel sides of a trapezium are 8.7 cm and 5.3 cm. If the perpendicular distance between them is 4.5 cm, what is its area?

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Solution

Lengths of the parallel sides of the trapezium are 8.7 cm and 5.3 cm.
Perpendicular distance between these sides = Height = 4.5 cm
Area of a trapezium = $\frac{1}{2}$ (Sum of lengths of parallel sides) × (Height)
= $\frac{1}{2}$ × (8.7 + 5.3) cm × 4.5 cm
= 31.5 sq cm

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The length of the parallel sides of a trapezium are 8.7 cm and 5.3 cm. If the perpendicular distance between them is 4.5 cm, what is its area?

Lengths of the parallel sides of the trapezium are 8.7 cm and 5.3 cm. Perpendicular distance between these sides = Height = 4.5 cm Area of a trapezium = 12 (Sum of lengths of parallel sides) × (Height) = 12 × (8.7 + 5.3) cm × 4.5 cm = 31.5 sq cm

Lengths of the parallel sides of the trapezium are 8.7 cm and 5.3 cm.
Perpendicular distance between these sides = Height = 4.5 cm
Area of a trapezium = $\frac{1}{2}$ (Sum of lengths of parallel sides) × (Height)
= $\frac{1}{2}$ × (8.7 + 5.3) cm × 4.5 cm
= 31.5 sq cm