The length of the parallel sides of a trapezium are in the ratio 3: 2 and the distance between them is 10 cm. If the area of the trapezium is 325 cm², find the length of the parallel sides.
Since the parallel sides are in the ratio 3:2 therefore, a=3x and b=2x.
Now, area of the trapezium,
325=12(2x+3x)×10
⇒(2x+3x)×10=650
⇒5x=65
⇒x=13
∴a=2×x=2×13=26
∴b=3×x=3×13=39
Hence, the parallel sides are 26 cm and 39 cm.