Question

The length of the parallel sides of a trapezium in the ratio $4:7$. If the heights of trapezium is $14m$ and its area is $385sq.m$, find the length of its parallel sides.

Answer 1

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Let the parallel sides of trapezium be $4x$ and $7x$

Height $=DE=14$ m (given)

Area $=385m^2$ (given)

Area of trapazium = $\frac{1}{2}(AB+CD)\times DE$

$\Rightarrow 385=\frac{1}{2}(7x+4x)\times 14$

$\Rightarrow 11\times 7x=385$

$\Rightarrow x=5m$

$\therefore$ the sides are $4x=4\times 5=20m$

$7x=7\times 5=35m$