The length of the perpendicular drawn from the point P(a, b, c) from z-axis is

$\sqrt{a^{2} + b^{2}}$

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$\sqrt{b^{2} + c^{2}}$

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$\sqrt{a^{2} + c^{2}}$

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$\sqrt{a^{2} + b^{2} + c^{2}}$

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Solution

The correct option is A
$\sqrt{a^{2} + b^{2}}$

The length of the perpendicular drawn from the point P(x, y, z)from z-axis

is given by $\sqrt{y^{2} + x^{2}}$

Thus, the length of the perpendicular drawn from the point P(a, b, c) from

z-axis is $\sqrt{a^{2} + b^{2}}$

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Similar questions

Q. The length of the perpendicular drawn from the point P(a, b, c) from z-axis is

(a)

\sqrt{a^{2} + b^{2}}

(b)

\sqrt{b^{2} + c^{2}}

(c)

\sqrt{a^{2} + c^{2}}

(d)

\sqrt{a^{2} + b^{2} + c^{2}}

Q. The distance of the point P (a, b, c) from the x-axis is
(a)

\sqrt{b^{2} + c^{2}}

(b)

\sqrt{a^{2} + c^{2}}

(c)

\sqrt{a^{2} + b^{2}}

(d) none of these

Q. In

△ A B C, b^{2} c o s 2 A - a^{2} c o s 2 B

The bond disscioation energies of molecules $A_{2}, B_{2} a n d C_{2}$ are 945, 158, 498KJ/ mole respectively.if so, the correct decreasing order of their bond orders is

The distance between points $(a + b, b + c)$ and $(a - b, c - b)$ is :

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The length of the perpendicular drawn from the point P(a, b, c) from z-axis is

The correct option is A √a2+b2 The length of the perpendicular drawn from the point P(x, y, z)from z-axis is given by √y2+x2 Thus, the length of the perpendicular drawn from the point P(a, b, c) from z-axis is √a2+b2

The correct option is A
$\sqrt{a^{2} + b^{2}}$

The length of the perpendicular drawn from the point P(x, y, z)from z-axis

is given by $\sqrt{y^{2} + x^{2}}$

Thus, the length of the perpendicular drawn from the point P(a, b, c) from

z-axis is $\sqrt{a^{2} + b^{2}}$