Question

The length of the seconds pendulum on the surface of earth is 1m. Its length on the surface of the moon is

• A. $1/36m$
• B. $1/6m$
• C. $6m$
• D. $36m$

Answer 1

The correct option is B $1/6m$

$T_E=T_M\Rightarrow 2\pi \sqrt{\frac{l_E}{g_E}}=2\pi \sqrt{\frac{l_M}{g_M}}\Rightarrow 2\pi \sqrt{\frac{1}{g}}=2\pi \sqrt{\frac{l_M}{g/6}}\Rightarrow l_M=\frac{1}{6}m$