Question

The length of the shaded rectangle is $\left(\frac{1}{10}\right)$ of the bigger rectangle and its breadth is 0.001 times the bigger rectangle. If the area of the bigger rectangle is $10000m^2$. Find the area of the shaded rectangle.

Answer 1

Let the length and breadth of the bigger rectangle be $a$ meters and $b$ meters respectively
As per the question.

The length of the shaded rectangle is $\left(\frac{1}{10}\right)$ of the bigger rectangle.

The length of the shaded rectangle is $0.1\times a$ meters.

The breadth of the shaded rectangle is 0.001 times the bigger rectangle.

The breadth of the shaded rectangle is $0.001\times b$ meters.

Area of the given bigger rectangle $=a\times b$ metres $=10000m^2$

Area of the shaded rectangle $=\left(0.1a\right)\times \left(0.001b\right)$
$=\left(0.0001\right)\times \left(ab\right)$
$=\left(0.0001\right)\times \left(10000\right)$
$=1m^2$
So, the area of the shaded rectangle is $1m^2$.