The length of the shadow of a 4m high pole at a certain time is 5.2m. What is the height of the pole whose shadow at that time is 91m.

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Solution

Height of pole = 4 m
Length of shadow= 5.2 m

The tan of angle made at that time = height of pole / length of shadow

So tan a = 4/5.2

Similarly tan a = height of pole / 91 ( for the second pole)

On equating ,

4/5.2 = h/91

h=(91*4)/5.2 = 364/5.2
= 70

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The length of the shadow of a 4m high pole at a certain time is 5.2m. What is the height of the pole whose shadow at that time is 91m.

Height of pole = 4 m Length of shadow= 5.2 m The tan of angle made at that time = height of pole / length of shadow So tan a = 4/5.2 Similarly tan a = height of pole / 91 ( for the second pole) On equating , ​​​​​​4/5.2 = h/91 h=(91*4)/5.2 = 364/5.2 = 70 Like if satisfied

Height of pole = 4 m
Length of shadow= 5.2 m

The tan of angle made at that time = height of pole / length of shadow

So tan a = 4/5.2

Similarly tan a = height of pole / 91 ( for the second pole)

On equating ,

4/5.2 = h/91

h=(91*4)/5.2 = 364/5.2
= 70

Like if satisfied