The length of the tangent drawn from a point 8 cm away from the center of a circle of radius 6 cm is $2 \sqrt{7}$ cm.

√7 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2√7 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
√7 cm

Given that AO = 8 cm, BO = 6 cm

Applying Pythagoras theorem

${A B}^{2} = {A O}^{2} - {B O}^{2}$

${A B}^{2} = 8^{2} - 6^{2}$

$\Rightarrow {A B}^{2} = 64 - 36 = 28$

$A B = 2 \sqrt{7}$ cm

Suggest Corrections

Similar questions

State true or false.
The length of the tangent drawn from a point 10 cm away from the center of a circle of radius 6 cm is 8 cm.

The length of tangent drawn from an external point P to a circle, with centre O, is 8 cm. If the radius of the circle is 6 cm, then the length of OP (in cm) is:

The length of the tangent drawn to a circle with radius $7 c m$ from a point $25 c m$ away from the centre is ___ $c m .$

A point P is 10 cm away from the center of a circle. The length of the tangent drawn from P to the circle is 8 cm. The radius of the circle is equal to ____.

Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct a pair of tangents to the circle and find their lengths.

Join BYJU'S Learning Program

The length of the tangent drawn from a point 8 cm away from the center of a circle of radius 6 cm is 2√7 cm.

The correct option is A √7 cm Given that AO = 8 cm, BO = 6 cm Applying Pythagoras theorem AB2=AO2–BO2 AB2=82–62 ⇒AB2=64–36=28 AB=2√7 cm

The length of the tangent drawn from a point 8 cm away from the center of a circle of radius 6 cm is $2 \sqrt{7}$ cm.

The correct option is A
√7 cm

Given that AO = 8 cm, BO = 6 cm

Applying Pythagoras theorem

${A B}^{2} = {A O}^{2} - {B O}^{2}$

${A B}^{2} = 8^{2} - 6^{2}$

$\Rightarrow {A B}^{2} = 64 - 36 = 28$

$A B = 2 \sqrt{7}$ cm