The length of the tangent drawn from a point $8 c m$ away from the centre of a circle of radius $6 c m$ is

√7 cm

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2√7 cm

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Solution

The correct option is
B

2√7 cm

Given that $A O = 8 c m, B O = 6 c m$

Applying Pythagoras theorem in $△$ ABO,

${A B}^{2} = {A O}^{2} - {B O}^{2}$

$\Rightarrow {A B}^{2} = 8^{2} - 6^{2}$

$\Rightarrow {A B}^{2} = 64 - 36 = 28$

$\Rightarrow A B = 2 \sqrt{7} c m$

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The length of the tangent drawn from a point 8 cm away from the centre of a circle of radius 6 cm is

The correct option is B 2√7 cm Given that AO=8 cm, BO=6 cm Applying Pythagoras theorem in △ABO, AB2=AO2–BO2 ⇒AB2=82–62 ⇒AB2=64–36=28 ⇒AB=2√7 cm

The length of the tangent drawn from a point $8 c m$ away from the centre of a circle of radius $6 c m$ is

The correct option is
B

2√7 cm

Given that $A O = 8 c m, B O = 6 c m$

Applying Pythagoras theorem in $△$ ABO,

${A B}^{2} = {A O}^{2} - {B O}^{2}$

$\Rightarrow {A B}^{2} = 8^{2} - 6^{2}$

$\Rightarrow {A B}^{2} = 64 - 36 = 28$

$\Rightarrow A B = 2 \sqrt{7} c m$