Question

The length ofa rectangle is four times its width. If the perimeter of the rectangleis60 metre, find thelength and breadth of the rectangle

Answer 1

$$\begin{gathered} \mathrm{Let}\mathrm{the}\mathrm{breadth}\left(\mathrm{width}\right)\mathrm{of}\mathrm{rectangle}\mathrm{be}\mathrm{x}\mathrm{m} \\ \mathrm{Then},\mathrm{Length}\mathrm{of}\mathrm{rectangle}\mathrm{be}4\mathrm{x}\mathrm{m} \\ \mathrm{Perimeter}\mathrm{of}\mathrm{rectangle}=60\mathrm{m} \\ \Rightarrow 2(4\mathrm{x}+\mathrm{x})=60\left[\because \mathrm{Perimeter}\mathrm{of}\mathrm{rectangle}=2(\mathrm{Length}+\mathrm{Breadth})\right] \\ \Rightarrow 2\left(5\mathrm{x}\right)=60 \\ \Rightarrow 10\mathrm{x}=60 \\ \Rightarrow \boxed{\mathbf{x}\mathbf{=}\mathbf{6}} \\ \mathbf{So}\mathbf{,}\mathbf{}\mathbf{Breadth}\mathbf{=}\mathbf{6}\mathbf{m} \\ \mathbf{Length}\mathbf{=}\mathbf{6}\mathbf{\times }\mathbf{4}\mathbf{=}\mathbf{24}\mathbf{m} \end{gathered}$$