Question

Question 5
The lengths of 62 leaves of a plant are measured in millimetres and the data is represented in the following table.

$\begin{array}{cc}Length\left(inmm\right)& Numberofleave\\ 118-126& 8\\ 127-135& 10\\ 136-144& 12\\ 145-153& 17\\ 154-162& 7\\ 163-171& 5\\ 172-180& 3\end{array}$

Draw a histogram to represent the data above.

Answer 1

The given frequency distribution is in the inclusive form. First, we convert it into exclusive form.
Now, adjusting factor $=\frac{127-126}{2}=\frac{1}{2}=0.5$
So, we subtract 0.5 from each lower limit and add 0.5 to each upper limit.
The table for continuous grouped frequency distribution is given below.

$\begin{array}{cc}Length\left(inmm\right)& Numberofleaves\\ 117.5-126.5& 8\\ 126.5-135.5& 10\\ 135.5-144.5& 12\\ 144.5-153.5& 17\\ 153.5-162.5& 7\\ 162.5-171.5& 5\\ 171.5-180.5& 3\end{array}$

Thus, the given data becomes in the exclusive form.
Along the horizontal axis, we represent the class intervals of length on some suitable scale.
The corresponding frequencies of the number of leaves are represented along the Y-axis on a suitable scale.
The given intervals start with 117.5 - 126.5. It means that there is some break $(\approx )$ indicated near the origin to signify the graph is drawn with ascale beginning at 117.5.

A histogram of the given distribution is given below.