Question

The lengths of the diagonals of a rhombus are $60cm$ and $80cm$. Find the perpendicular distance between the opposite sides of rhombus.

Answer 1

The area of Rhombus is $\frac{1}{2}60\times 80=240c{m}^2$

The side of Rhombus is hypotenuse of semi diagonals

$i.e.,Sid{e}^2={30}^2+{40}^{2}side=50$

The area can also be given as $\frac{1}{2}side\times height\frac{1}{2}\times 50\times h=240height=9.6cm$