Question

The lengths of the intercepts on the co-ordinate axes made by the plane $5x+2y+z-13=0$ are

• A. $5,2,1$ unit
• B. $\frac{13}{5},\frac{13}{2},13$ unit
• C. $\frac{5}{13},\frac{2}{13},\frac{1}{13}$ unit
• D. $1,2,5$ unit

Answer 1

Answer: (B)

$\frac{13}{5},\frac{13}{2},13$ unit

Solution:

Given that:

$5x+2y+z-13=0$

or, $\frac{x}{\frac{13}{5}}+\frac{y}{\frac{13}{2}}+\frac{z}{13}=1$

$\therefore$ Lengths of intercepts are $\frac{13}{5},\frac{13}{2}$ and $13.$

Hence, B is the correct option.