The lengths of the parallel sides of a trapezium are $30$ centimetres, $10$ centimetres and the distance between them is $20$ centimetres. What is its area?

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Solution

Area of a trapezium $= \frac{1}{2} \times$ Sum of parallel sides $\times$ distance between them.
$= \frac{1}{2} \times (30 + 10) \times 20$
$= \frac{1}{2} \times 40 \times 20$
$= 400$ sq.cms

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The lengths of the parallel sides of a trapezium are 30 centimetres, 10 centimetres and the distance between them is 20 centimetres. What is its area?

Area of a trapezium=12×Sum of parallel sides× distance between them.=12×(30+10)×20=12×40×20=400sq.cms

The lengths of the parallel sides of a trapezium are $30$ centimetres, $10$ centimetres and the distance between them is $20$ centimetres. What is its area?

Area of a trapezium $= \frac{1}{2} \times$ Sum of parallel sides $\times$ distance between them.
$= \frac{1}{2} \times (30 + 10) \times 20$
$= \frac{1}{2} \times 40 \times 20$
$= 400$ sq.cms