The lengths of the sides of a right angled triangle are all given in natural numbers. If two of these numbers are odd and they differ by 50, then the least possible value for the third side is

A)61

B)60

C)51

D)50

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Solution

If there is a right angle triangle then there must be a pythagoren triplet.

Odd1 - Odd 2 = 50

I think the pythagorean triplet must be ( 11 , 60 , 61)

It is here proved also

61 - 11 (both are odd) = 50

So the least value of third side will be 60

Ans: b) 60

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The lengths of the sides of a right angled triangle are all given in natural numbers. If two of these numbers are odd and they differ by 50, then the least possible value for the third side is A)61 B)60 C)51 D)50

If there is a right angle triangle then there must be a pythagoren triplet. Odd1 - Odd 2 = 50 I think the pythagorean triplet must be ( 11 , 60 , 61) It is here proved also 61 - 11 (both are odd) = 50 So the least value of third side will be 60 Ans: b) 60

The lengths of the sides of a right angled triangle are all given in natural numbers. If two of these numbers are odd and they differ by 50, then the least possible value for the third side is

A)61

B)60

C)51

D)50

If there is a right angle triangle then there must be a pythagoren triplet.

Odd1 - Odd 2 = 50

I think the pythagorean triplet must be ( 11 , 60 , 61)

It is here proved also

61 - 11 (both are odd) = 50

So the least value of third side will be 60

Ans: b) 60