The lengths of the sides of a triangle are 11 cm, 13 cm, and 12 cm. Calculate the length of the median drawn to the larger side.

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Solution

let $a = 11, b = 13, c = 12$ .

The length of median drawn to the largest side is

$m_{B} = \frac{1}{2} \sqrt{2 a^{2} + 2 c^{2} - b^{2}}$

$= \frac{1}{2} \sqrt{2 (121) + 2 (144) - 169}$

$= \sqrt{367}$

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The lengths of the sides of a triangle are 11 cm, 13 cm, and 12 cm. Calculate the length of the median drawn to the larger side.

let a=11,b=13,c=12. The length of median drawn to the largest side is mB=12√2a2+2c2−b2=12√2(121)+2(144)−169=√367

let $a = 11, b = 13, c = 12$ .

The length of median drawn to the largest side is

$m_{B} = \frac{1}{2} \sqrt{2 a^{2} + 2 c^{2} - b^{2}}$

$= \frac{1}{2} \sqrt{2 (121) + 2 (144) - 169}$

$= \sqrt{367}$