Question

The lengths of the sides of a triangle are 33cm , 44cm and 55cm respectively . Find the area of the triangle and hence find the height corresponding to the circle measuring 44 cm.

Answer 1

Area of triangle=$\sqrt{s(s-a)(s-b)(s-c)}$

Here, $s=\frac{33+44+55}{2}=66cm$

Therefore area $=\sqrt{66(66-33)(66-44)(66-55)}$

$=\sqrt{66\left(33\right)\left(22\right)\left(11\right)}$

$=726c{m}^2$

Now area $=726c{m}^2$

and,base$=44cm$

Therefore height $=\frac{area\left(2\right)}{base}$

$=33cm$