The lengths of the sides of a triangle are in the ratio $2 : 3 : 4$ . If the perimeter of triangle is $63 c m$ , find the lengths of the sides of triangles.

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Solution

Given, perimeter of triangle $=$ $63 c m$
Ratio of length of sides of a triangle $=$ $2 : 3 : 4$
Length of first side of triangle $=$ $(\frac{2}{2 + 3 + 4}) \times 63 c m = 14 c m$
Length of second side of triangle $=$ $(\frac{3}{2 + 3 + 4}) \times 63 c m = 21 c m$
Length of third side of triangle $=$ $(\frac{4}{2 + 3 + 4}) \times 63 c m = 28 c m$
Hence, lengths of sides of triangles are $14 c m, 21 c m$ and $28 c m$ respectively.

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