wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The lengths of two parallel chords of a circle are 6 cm and 8 cm. The smaller chord is at a distance of 4 cm from the centre,then the radius of the circle is?

A
10 cm
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
B
5 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3 cm
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
D
None of these
No worries! Weā€˜ve got your back. Try BYJUā€˜S free classes today!
Open in App
Solution

The correct option is B 5 cm
Let AB and CD are two parallel chords of a circle having length 6 cm and 8 cm and radius is O.

Let the radius of the circle be r.

Now draw OP perpendicular to AB and OQ perpendicular to CD.

since OP is perpendicular to AB and OQ is perpendicular to CD and AB || CD

From figure, OP = 4 cm.

P, Q are the mid points of AB and CD respectively. [perpendicular from center bisects the chord]

So AP=PB=AB2=62=3cm

CQ=QD=CD2=82=4cm

Now in triangle OAP

OA2=OP2+AP2

r2=16+9

r=16+9

r=5cm

So, option B is the answer.



835943_92797_ans_cf41079e865b4a2984394253969b7501.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Intersection between Secants
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon