Question

The lengths of two parallel chords of a circle are $6$ cm and $8$ cm. If the smaller chord is at distance $4$ cm from the centre, what is the distance of the other chord from the centre?

Answer 1

There are two parallel chords of length $8$ cm and $6$ cm.

The distance between center and shortest chord $(6$cm chord$)$ is $4$cm.

So, the perpendicular distance from the center to the shortest chord is $4$cm.

The perpendicular line from center to chord divides chord into two equal

parts.

So, the radius of circle is $\sqrt{3^2+4^2}=5$.

Since the radius is $5$.

The distance from center to largest chord is $\sqrt{5^2-4^2}=3$.