Question

The letters forming the word $CLIFTON$ are placed at random in a row. The probability that the two vowels come together is

• A. $\frac{1}{7}$
• B. $\frac{2}{7}$
• C. $\frac{3}{7}$
• D. $\frac{4}{7}$

Answer 1

The correct option is B $\frac{2}{7}$

Vowels $=I,O$
Keeping them together no. of ways of arrangements$=(7-1)!\ast 2!=6!\ast 2$
Total ways of arrangements $=7!$
$\Rightarrow P=6!\ast 2/7!=2/7$