The letters of the word $" S W O R D^{'}$ are written on the similar cardboards. These cardboards are then mixed and put upside down so that no one can see the letters. Rajni takes one of cardboards. What is the probability that it has the letter $^{'} R^{'}$ on it?

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Solution

The Letters of the word $\Rightarrow$ SWORD
then total letter = $5 = n (E)$
The letter $R = 1 = n (S)$
Then, Probability $P (E) = \frac{n (s)}{n (E)}$
$P (E) = \frac{1}{5}$
Hence, this is the answer

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The letters of the word "SWORD′ are written on the similar cardboards. These cardboards are then mixed and put upside down so that no one can see the letters. Rajni takes one of cardboards. What is the probability that it has the letter ′R′ on it?

The Letters of the word ⇒ SWORDthen total letter = 5=n(E)The letter R=1=n(S)Then, Probability P(E)=n(s)n(E)P(E)=15Hence, this is the answer

The letters of the word $" S W O R D^{'}$ are written on the similar cardboards. These cardboards are then mixed and put upside down so that no one can see the letters. Rajni takes one of cardboards. What is the probability that it has the letter $^{'} R^{'}$ on it?

The Letters of the word $\Rightarrow$ SWORD
then total letter = $5 = n (E)$
The letter $R = 1 = n (S)$
Then, Probability $P (E) = \frac{n (s)}{n (E)}$
$P (E) = \frac{1}{5}$
Hence, this is the answer