Question

The letters that form the word $\text{ALGEBRA}$ are placed in a bowl. The probability of picking a letter other than “A” is.

• A. $\frac{2}{7}$
• B. $\frac{5}{7}$
• C. $\frac{1}{7}$
• D. $\frac{6}{7}$

Answer 1

The correct option is B $\frac{5}{7}$

Letters A, L, G, E, B, R, A are placed in a bowl.
$\text{To Find:}$ Probability of NOT picking the letter “A”, i.e., $\text{P (not A)}$

Here,
Sample Space = $\left\{\text{A, L, G, E, B, R, A}\right\}$
$\therefore$ Total number of equally likely outcomes= $7$

Favorable outcomes= $\left\{\text{L, G, E, B, R}\right\}$
$\therefore$ Number of favorable outcomes= $5$

Hence, the probability of picking a letter from the bowl which is NOT “A” is
$\text{P (not A)}=\frac{\text{Number of favorable outcomes}}{\text{Total number of equally likely outcomes}}$
$\Rightarrow \text{P (not A)}=\frac{5}{7}$