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Hydrides of Nitrogen

The Lewis bas...

Question

The Lewis base strength of nitrogen halide is the maximum for :

A

N C l_{3}

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B

N B r_{3}

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C

N I_{3}

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D

N F_{3}

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Solution

The correct option is C $N I_{3}$
Since, F has the highest electronegativity and I has the least, the electrons on nitrogen in $N F_{3}$ are least available and in $N I_{3}$ , they are most available for protonation making $N I_{3}$ the most basic.

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Similar questions

Q. The hydrolysis of

N F_{3}

doesn't takes place where as hydrolysis of

N B r_{3}

N I_{3}

N C l_{3}

Q. Assertion :Amongst the trihalides of nitrogen,

N F_{3}, N C l_{3}, N B r_{3}

N I_{3}, N F_{3}

is least basic. Reason: In

N F_{3}

, the fluorine has the highest value of electronegativity and thus the lone pair of electrons on N-atoms is strongly bound.

Read the above assertion and reason and choose the correct option regarding it.

Q. The hydrolysis of

{N F}_{3}

does not takes place where as hydrolysis of

{N B r}_{3}, {N I}_{3}, {N C I}_{3}

N F_{3}

N {C l}_{3}

N I_{3}

are readily hydrolysed and are explosives. Explain.

State True or False.

N F_{3}

N C l_{3}

N I_{3}

are explosive in nature.

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