Question

The lid of a rectangular box of sides $40cmby10cm$ is sealed all around with tape.What is the length of tape required

Answer 1

Length of tape required is same as perimeter of rectangular box.

Then perimeter of rectangle $=2(L+B)$

$$\begin{gathered} =2(40+10)cm \\ =(2\times 50)cm \\ =100cm \\ =1m(S\mathrm{in}ce100cm=1m) \end{gathered}$$

Hence length of required tape is $100cmor1m.$