The lid of a rectangular box of sides $40 c m$ by $10 c m$ is sealed all round with tape. What is the length of the tape required?

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Solution

Length of tape = Perimeter of lid

$= 2 (l + b)$

$= 2 (40 + 10)$

$= 2 \times 50$

$= 100 c m$

$= 1 m$

Hence, this is the answer.

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The lid of a rectangular box of sides 40cm by 10cm is sealed all round with tape. What is the length of the tape required?

Length of tape = Perimeter of lid =2(l+b) =2(40+10) =2×50 =100cm =1 mHence, this is the answer.

The lid of a rectangular box of sides $40 c m$ by $10 c m$ is sealed all round with tape. What is the length of the tape required?

Length of tape = Perimeter of lid

$= 2 (l + b)$

$= 2 (40 + 10)$

$= 2 \times 50$

$= 100 c m$

$= 1 m$

Hence, this is the answer.