The ligand $N (C H_{2} C H_{2} N H_{2})_{3}$ is:

tetradentate

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

tridentate

No worries! We‘ve got your back. Try BYJU‘S free classes today!

pentadentate

No worries! We‘ve got your back. Try BYJU‘S free classes today!

bidentate

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A tetradentate

Number of donor atoms in $N (C H_{2} C H_{2} N H_{2})_{3}$ is four. Hence it is a tetradentate ligand. Each nitrogen atom is a donor atom.

Suggest Corrections

Similar questions

N (C H_{2} C H_{2} N H_{2})_{3}

n C H_{2} = C H_{2} \to [- C H_{2} - C H_{2} -]_{n}

n C H_{2} = C H_{2} \to (- C H_{2} - C H_{2} -)_{n}

100

100

n C H_{2} = C H_{2} \to (C H_{2} - C H_{2})_{n}

100

n C H_{2} = C H_{2} \to - (C H_{2} - C H_{2})_{n} -

Join BYJU'S Learning Program