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Question

The light from a torch is normally incident on the surface at intensity of illumination I1. If the surface is tilted to 45 from initial position, then what will be intensity of illumination I2 on the surface in terms of I1 ?


Correct Answer
A
I2=I12
Your Answer
B
I2=I1
Your Answer
C
I2=2I1
Your Answer
D
I2=4I1

Solution

The correct option is A I2=I12

Intensity I=PA where P is the power of incident light and A is the area of surface.

Then, I1=PA
and I2=PA
From the diagram, Acos45=A
I2=PAcos45=I12

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