The light from the sun is found to have a maximum intensity near the wavelength of $470 n m$ . Assuming the surface of the sun as a black body, the temperature of the sun is __________.
[Wien's constant $b = 2.898 \times 10^{- 3} m K$ ]

5800 K

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6050 K

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6166 K

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6500 K

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Solution

The correct option is C $6166 K$
Given : $λ_{m} = 470 n m = 4.70 \times 10^{- 7} m$ $b = 2.898 \times 10^{- 3} m K$
From Wien's displacement law, $T λ_{m} = b$
We get, temperature of sun $T = \frac{b}{λ_{m}}$
$∴$ $T = \frac{2.898 \times 10^{- 3}}{4.70 \times 10^{- 7}} = 6166$ $K$

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The light from the sun is found to have a maximum intensity near the wavelength of 470nm. Assuming the surface of the sun as a black body, the temperature of the sun is __________.[Wien's constant b=2.898×10−3mK]

The correct option is C 6166KGiven : λm=470nm=4.70×10−7m b=2.898×10−3mKFrom Wien's displacement law, Tλm=bWe get, temperature of sun T=bλm∴ T=2.898×10−34.70×10−7=6166 K

The light from the sun is found to have a maximum intensity near the wavelength of $470 n m$ . Assuming the surface of the sun as a black body, the temperature of the sun is __________.
[Wien's constant $b = 2.898 \times 10^{- 3} m K$ ]

The correct option is C $6166 K$
Given : $λ_{m} = 470 n m = 4.70 \times 10^{- 7} m$ $b = 2.898 \times 10^{- 3} m K$
From Wien's displacement law, $T λ_{m} = b$
We get, temperature of sun $T = \frac{b}{λ_{m}}$
$∴$ $T = \frac{2.898 \times 10^{- 3}}{4.70 \times 10^{- 7}} = 6166$ $K$