The light of wavelength 6328 Å is incident on a slit of width 0.2 mm perpendicularly, the angular width of central maxima will be

[MP PMT 1987; Pb. PMT 2002]

0.36°

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0.18°

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0.72°

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0.09°

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Solution

The correct option is A
0.36°

Total width of central maxima= θ=0.36°

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Similar questions

The light of wavelength 6328 Å is incident on a slit of width 0.2 mm perpendicularly, the angular width of central maxima will be

[MP PMT 1987; Pb. PMT 2002]

6328 A^{o}

0.2 m m

6328 o A

0.2 m m

9.0

˙ A

589.3 nm

0.1 mm

1 m

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