The light rays having photons of energy 1.8 $e V$ are falling on metal surface having a work function 1.2 $e V$ . What is the stopping potential to be applied in order to stop the emitting electrons?

V

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1.2

V

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0.6

V

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1.4

V

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Solution

The correct option is B 0.6 $V$
Energy required to stop the emitting electrons is equal to the difference of the metal work function and the energy of the photons.
$e V_{S} = h f - h f_{o}$
$e V_{S} = 1.8 - 1.2 = 0.6 V$
So, the answer is option (C).

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The light rays having photons of energy 1.8 eV are falling on metal surface having a work function 1.2 eV. What is the stopping potential to be applied in order to stop the emitting electrons?

The correct option is B 0.6VEnergy required to stop the emitting electrons is equal to the difference of the metal work function and the energy of the photons.eVS=hf−hfoeVS=1.8−1.2=0.6VSo, the answer is option (C).

The light rays having photons of energy 1.8 $e V$ are falling on metal surface having a work function 1.2 $e V$ . What is the stopping potential to be applied in order to stop the emitting electrons?

The correct option is B 0.6 $V$
Energy required to stop the emitting electrons is equal to the difference of the metal work function and the energy of the photons.
$e V_{S} = h f - h f_{o}$
$e V_{S} = 1.8 - 1.2 = 0.6 V$
So, the answer is option (C).