Question

The limit of $\frac{x^2-1}{x-1}$ as $x$ approaches $1$ as a limit is

• A. $0$
• B. Indeterminate
• C. $x-1$
• D. $2$
• E. $1$

Answer 1

The correct option is D $2$

$\frac{x^2-1}{x-1}=\frac{(x+1)(x-1)}{x-1}=x+1$, for all $x\ne 1$;
the limit of $x+1$ as $x\to 1$ is $2$, so that (d) is the correct choice.