Question

The limit of resolution of 100 cm telescope for $\lambda =5000\mathring{A}$ is approximately equal to

• A. 0.13"
• B. 0.3"
• C. 1"
• D. 1.4"

Answer 1

The correct option is A 0.13"

Given,

$\lambda =5000\times {10}^{-10}=5\times {10}^{-7}m$

$D=100cm=1m$

The limit of resolution of telescope

$\theta =\frac{1.22\lambda }{D}$

$\theta =\frac{1.22\times 5\times {10}^{-7}}{1}$

$\theta =6.1\times {10}^{-7}radian$

$\theta ={0.13}^{\prime \prime }$

The correct option is A.