CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The limit of the following series as x approaches π2 is
f(x)=xx33!+x55!x77!+.....

A
2π3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
π2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
π3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1
f(x)=xx33!+x55!x77!...
f(x)=sinx
limxπ2f(x)=limxπ2sinx=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems on Integration
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon